已知函数f(x)满足满足f(x)=f′(1)ex-1-f(0)x+x2;则f(x)的解析式为________.
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f(x)=
解析分析:把给出的函数求导,在导函数中取x=1可求出f(0)=1,在给出的等式中,取x=0,利用f(0)=1可求f′(1),则函数解析式可求.
解答:由f(x)=f′(1)ex-1-f(0)x+x2,得:f′(x)=f′(1)ex-1-f(0)+x,令x=1得:f(0)=1;在f(x)=f′(1)ex-1-f(0)x+x2中,取x=0,得f(0)=f′(1)e-1=1,∴f′(1)=e所以f(x)的解析式为.故