已知等比数列{an}中,若a1005?a1007=4,则该数列的前2011项的积为A.42011B.±42011C.22011D.±22011
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D
解析分析:根据等比数列的性质a1005?a1007=a1?a2011=a2?a2010=…=a21006,求出a1006=±2,a1?a2?a3…a2000?a2001=41005?a1006,即可求出结果.
解答:∵a1005?a1007=a21006=4∴a1006=±2∴a1?a2?a3…a2010?a2011=(a1?a2011)?(a2?a2010)…(a1005?a1007)?a1006=41005?a1006当a1006=2时a1?a2?a3…a2010?a2011=(a1?a2011)?(a2?a2010)…(a1005?a1007)?a1006=41005?a1006=22011当a1006=-2时a1?a2?a3…a2010?a2011=(a1?a2011)?(a2?a2010)…(a1005?a1007)?a1006=41005?a1006=-22011故选D.
点评:本题考查了等比数列的性质,但注意要分类讨论,属于基础题.