已知(z-x)2=4(x-y)(y-z),则A.x,y,z成等差数列B.x,y,z成等比数列C.成等差数列D.成等比数列
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A
解析分析:已知(z-x)2=4(x-y)(y-z),变形为[(x-y)+(y-z)]2=4(x-y)(y-z),再化为[(x-y)-(y-z)]2=0,即可得出结论.
解答:∵(z-x)2=4(x-y)(y-z),∴[(x-y)+(y-z)]2=4(x-y)(y-z),化为[(x-y)-(y-z)]2=0,∴x-y=y-z,∴2y=x+z,∴x,y,z成等差数列.故选A.
点评:正确变形和掌握等差数列的定义是解题的关键.