已知函数f(x)=√2cos(x-π/12）,x∈R

网友回答

解；f(π/3)=√2cos(π/3-π/12)
=√2cos(π/4)
=√2*√2/2=1
∵cost=3/5
且t∈（3π/2,2π）
∴sint=-4/5
f(t-π/6)=√2cos(t-π/6-π/12)
=√2cso(t-π/4)
=√2costcosπ/4+√2sintsinπ/4
=3/5-4/5
=-1/5