化简 cos(π/6-x)-根号3sin(π/6-x)

网友回答

原式=2[1/2*c0s(π/6-x)-√3/2*sin(π/6-x)]
=2[cos(π/6-x)cosπ/3-sin(π/6-x)sinπ/3]
=2cos(π/6-x+π/3)
=2cos(π/2-x)
=2sinx
======以下答案可供参考======
供参考答案1:
原式=2[(1/2)cos(π/6－x)－(√3/2)sin(π/6－x)]
=2[sin(π/6)cos(π/6－x)－cos(π/6)sin(π/6－x)]
=2sin[(π/6)－(π/6－x)]
=2sin(x)