若{an}是公差为1的等差数列,则{a2n-1+2a2n}是A.公差为3的等差数列B.公差为4的等差数列C.公差为6的等差数列D.公差为9的等差数列
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C
解析分析:构造新数列cn=a2n-1+2a2n,求出相邻两项的差,利用等差数列的定义,即可得到结论.
解答:设{an}的公差为d,则d=1,设cn=a2n-1+2a2n,则cn+1=a2n+1+2a2n+2,∴cn+1-cn=a2n+1+2a2n+2-a2n-1-2a2n=6d=6,故选C.
点评:本题重点考查等差关系的确定,考查等差数列的定义,直接利用等差数列的定义判断是关键.