如图,在3角形abc中,角acb为100度ac等于ae,bc等于bd角dce等于

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∵AC=AE,BC=BD
∴∠ACE=∠AEC,∠BCD=∠CBD
∴∠ACE+∠BCD=∠AEC+∠CBD=180°-∠DCE,
∠ACE+∠BCD=∠ACB+∠DCE=100°+∠DCE,
∴180°-∠DCE=100°+∠DCE,
解得∠DCE=40°.
选D.