(1/2)椭圆ax^2+bx^2=1与直线x+y-1=0相交于A,B两点,C是AB的中点,若|AB|

发布时间:2021-02-25 22:39:31

(1/2)椭圆ax^2+bx^2=1与直线x+y-1=0相交于A,B两点,C是AB的中点,若|AB|=2倍根号2,OC的斜率为根号2/...(1/2)椭圆ax^2+bx^2=1与直线x+y-1=0相交于A,B两点,C是AB的中点,若|AB|=2倍根号2,OC的斜率为根号2/2,求椭圆

网友回答

A(x1,y1)B(x2,y2)
a(x1-x2)(x1+x2)+b(y1-y2)(y1+y2)=0,(y1-y2)/(x1-x2)= -1
(y1+y2)/(x1+x2)=√2/2,a√2=b
|AB|=2√2=√[(x1+x2)^2-4x1x2]√2
a=(2+√2)/2,b=1+√2
方程[(2+√2)/2]x^2+(1+√2)y^2=1
======以下答案可供参考======
供参考答案1:
椭圆方程为[(2+√2)/2]x^2+(1+√2)y^2=1
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