设Sn=-1+3-5+7-…+(-1)n(2n-1),则Sn=________.
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(-1)n?n
解析分析:当n是偶数时,Sn=(-1+3)+(-5+7)+…+[-(2n-3)+(2n-1)]=.当n是奇数时,Sn=(-1+3)+(-5+7)+…+[-(2n-5)+(2n-3)]+(-1)×(2n-1)=-n.由此可知Sn=(-1)n?n.
解答:当n是偶数时,Sn=(-1+3)+(-5+7)+…+[-(2n-3)+(2n-1)]=2+2+…+2(共项)=.当n是奇数时,Sn=(-1+3)+(-5+7)+…+[-(2n-5)+(2n-3)]+(-1)×(2n-1)=2+2+…+2(共有项)-(2n-1)==n-1-2n+1=-n.∴Sn=(-1)n?n.故