化简sin(x+2π/3)+2sinx-√3 cos(π/3-x) 主要看过程谢谢~

网友回答

=sinxcos2π/3+cosxsin2π/3+2sinx-√3(cosxcosπ/3+sinxsinπ/3)
=sinx *(-1/2+2 -√3*√3/2)+cosx * (√3/2-√3/2)
=0;或=sin(π/3-x) +2sinx-√3 cos(π/3-x)
=2sin(π/3-x) cosπ/3-2cos(π/3-x)sinπ/3+2sinx
=2sin(π/3-x-π/3)+2sinx
=-2sinx++2sinx
=0