设全集I={1,2,3,4,5,6,7},A={1,2,4,7},则CIB={4,5,6,7},CIA∩B=A.{1,2,3}B.{3,5,6}C.{3}D.{1,5

发布时间:2020-07-31 21:55:22

设全集I={1,2,3,4,5,6,7},A={1,2,4,7},则CIB={4,5,6,7},CIA∩B=A.{1,2,3}B.{3,5,6}C.{3}D.{1,5}

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C
解析分析:现根据B的补集和全集推理出集合B,然后求出集合A的补集,求出CI(A∩B)即可.

解答:根据全集I={1,2,3,4,5,6,7},CIB={4,5,6,7},得到B={1,2,3};而由A={1,2,4,7},得到CIA={3,5,6},则CI(A∩B)={3]故选C

点评:本题考查学生掌握补集、交集的定义及运算,锻炼了学生的推理能力,是一道基础题.
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