设全集U={4,5,6,7,8},集合M={5,8},N={1,3,5,7,9},则N∩(CUM)=A.{5}B.{7}C.{5,7}D.{5,8}

发布时间:2020-07-31 18:40:35

设全集U={4,5,6,7,8},集合M={5,8},N={1,3,5,7,9},则N∩(CUM)=A.{5}B.{7}C.{5,7}D.{5,8}

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B
解析分析:求出集合CUM,然后直接求解N∩(CUM)即可.

解答:因为全集U={4,5,6,7,8},集合M={5,8},所以CUM={4,6,7},N∩(CUM)={1,3,5,7,9}∩{4,6,7}={7},故选B.

点评:本题是基础题,考查集合的基本运算,补集与交集的求法,考查计算能力,常考题型.
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