设f(x)为可导函数且满足 limx→0 [f(1)-f(1-x)]/2x = -1 ,则曲线y=f

发布时间:2021-02-26 04:24:13

设f(x)为可导函数且满足 limx→0 [f(1)-f(1-x)]/2x = -1 ,则曲线y=f(x)在点(1,f(x))处切线的斜率是.a.2 b.-1 c.1/2 d.-2要过程.

网友回答

limx→0 [f(1)-f(1-x)]/2x
=1/2limx→0 [f(1)-f(1-x)]/x
=1/2f'(1)
=-1f'(1)=-2
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