求sin^4α+cos^2α+sin^2αcos^2α的值RT.最终答案为1,
网友回答
sin^4α+cos^2α+sin^2αcos^2α= sin^2α（ sin^2α+cos^2α）+cos^2α=sin^2α+cos^2α=1 ,不懂可以HI我
======以下答案可供参考======
供参考答案1:
(sinα)^4+(cosα)^2+(sinαcosα)^2
=(sinα)^4+(sinαcosα)^2+(cosα)^2
=(sinα)^2(sinα)^2+(sinαcosα)^2+(cosα)^2
=(sinα)^2[(sinα)^2+(cosα)^2]+(cosα)^2
=(sinα)^2×1+(cosα)^2
=1