(x+y)平方+2(x+1)+2y-1 因式分解RT

网友回答

(x+y)²+2(x+1)+2y-1
=(x+y)²+2x+2+2y-1
=(x+y)²+2x+2y+1
=(x+y)²+2(x+y)+1
=(x+y+1)²
======以下答案可供参考======
供参考答案1:
(x+y+1)平方
供参考答案2:
原式=x^2+2xy+y^2+2x+1+2y=(x+1)^2+2y(x+1)+y^2=(x+1+y)^2
供参考答案3:
原式=（x+y)²+2（x+y)+1
=(x+y+1)²