填空题如果数列{an}满足a1=3,an-an+1=5anan+1(n∈N*),则an

发布时间:2020-07-09 04:33:35

填空题如果数列{an}满足a1=3,an-an+1=5anan+1(n∈N*),则an=________.

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解析分析:将an-an+1=5anan+1两边同除以anan+1 得-=5,得出数列{}是等差数列,先求数列{}的通项公式,再求an解答:将an-an+1=5anan+1两边同除以anan+1 得-=5,∴数列{}是等差数列,=(n-1)×5=,an=故
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