∫x[ln(x²+2)-ln(2x+1)]dx

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∫x[ln(x²+2)-ln(2x+1)]dx=∫xln(x²+2)dx-∫xln(2x+1)dx=(1/2)∫ ln(x²+2)d(x²)-(1/2)∫ ln(2x+1)d(x²)=(1/2)x²ln(x²+2)-(1/2)∫ x²/(x²+2)d(x²)-(1/2)x²ln...