∫u/√(u^2-5)du不定积分怎么解

网友回答

∫u/√(u^2-5)du
=1/2∫1/√(u^2-5)du^2
=1/2∫1/√(u^2-5)d(u^2-5)
=√(u^2-5)+C
======以下答案可供参考======
供参考答案1:
∫u/√(u^2-5)du
=(1/2)∫(u^2-5)^(-1/2) d(u^2-5)
=(u^2-5)^(1/2) + C
=√(u^2-5) + C
供参考答案2:
∫u/√(u^2-5)du
=1/2∫1/√(u^2-5)d(u^2-5)=1/2*2(u^2-5)^(1/2)+C
=(u^2-5)^(1/2)+C