求不定积分.∫【 u^（1/2）+1】（u-1) du:

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∫【 u^（1/2）+1】（u-1) du
=∫[ u^（3/2）+u-u^（1/2）-1)] du
=∫ u^（3/2）du+∫udu-∫u^（1/2）du-∫1 du
=2/5 u^（5/2）+1/2 u^2-2/3 u^(3/2)-u+C