设u=(e^xy)(cos(x+y^2)),求du

网友回答

对x偏导du/dx=ye^xy(cos(x+y^2))+e^xy(-sin(x+y^2)) 偏导的那个a打不出来
对y偏导du/dy=xe^xy(cos(x+y^2))+e^xy(-sin(x+y^2))2y
du={ye^xy(cos(x+y^2))+e^xy(-sin(x+y^2))}dx+{xe^xy(cos(x+y^2))+e^xy(-sin(x+y^2))2y}dy 里面的小项没有整理...
======以下答案可供参考======
供参考答案1:
du={e^(xy)[ycos(x+y^2)-sin(x+y^2)]}dx+
{e^(xy)[xcos(x+y^2)-2ysin(x+y^2)]}dy