分解因式：yz(y-z)+zx(z-x)+xy(x-y)

推荐回答

xy(x-y)+yz(y-z)+zx(z-x)=xy(x-y)+yz(y-z)+zx[-(x-y)-(y-z)]=(x-y)(xy-xz)+(y-z)(yz-zx)=(x-y)(y-z)x+(y-z)(y-x)z=(x-y)(y-z)(x-z)