发布时间：2021-02-19 21:41:33
(本小题满分12分) 设a > 1，函数．
（1）求的反函数；
（2）若在[0，1]上的最大值与最小值互为相反数，求a的值；
（3）若的图象不经过第二象限，求a的取值范围．
解：(1) 由
∴
∴ ··································································· 4分
(2) ∵ a > 1 ∴ 在[0，1]上递增
∴ ，
∴ 即
∴ ······························································································· 8分
(3) 在y轴上的截距为
要使的图象不过第二象限，
只需
∴
∴
因此，a的取值范围为····································································· 12分
【解析】略