√[﹙lg3﹚³-lg9+1﹙lg√27+lg8-lg√1000﹚]/lg0.3lg1.2

网友回答

√[﹙lg3﹚^2-lg9+1]*﹙lg√27+lg8-lg√1000﹚]/lg0.3lg1.2
=√(lg3-1)^2*(3/2*lg3+3lg2-3/2)/(lg3-1)(lg12-1)
=(1-lg3)*3/2(lg3+2lg2-1)/[(lg3-1)(lg3+2lg2-1)]
=-3/2=-1.5√[(lg3)^2-lg9+1]=√(lg3-1)^2=1-lg3
lg√27+lg8-lg√1000=3/2*lg3+3lg2-3/2=3/2(lg3+2lg2-1)
lg0.3*lg1.2=(lg3-1)(lg12-1)=(lg3-1)(lg3+2lg2-1)
======以下答案可供参考======
供参考答案1:
1.5