三角形ABC中,角A=2角B=4角C

网友回答

∠A=2∠B=4∠C
∠B=1/2∠A
∠C=1/4∠A
∠A+∠B+∠C=180°
∠A+1/2∠A+1/4∠A=180°
∠A=720/7
∠B=720/14=360/7
∠C=720/28=180/7
======以下答案可供参考======
供参考答案1:
设∠C=x则∠B=2x ∠A=4x
x+2x+4x=180
7x=180
x=180/7
∠C=x=180/7
∠B=2x=360/7
∠A=4x=720/7