x-2/(x^2-9)(1+(2x-7/x^2-4x+4)÷(x+1)/(x+3)其中x=2010

网友回答

=(x-2)/(x+3)(x-3)× (x²+2x-3)/(x-2)² ×(x+3)/(x+1)
=(x-2)/(x+3)(x-3)×(x-3)(x+1)/(x-2)²×(x+3)/(x+1)
=1/(x-2)
当x=2010时
原式=1/(2010-2)
=1/2008