x[x+y][x+y]-x[x-y]² 分解因式是多少?要步奏讲解.要因式分解

网友回答

x[x+y][x+y]-x[x-y]²
＝x[(x+y)²－(x-y)²]
=x[(x+y+(x-y)][(x+y)-(x-y)]
=x(2x)(2y)
=4x²y
======以下答案可供参考======
供参考答案1:
x[x+y][x+y]-x[x-y]²
=x[(x+y)²-(x-y)²]
=x(x+y+x-y)(x+y-x+y)
=4x²y
供参考答案2:
x[x+y][x+y]-x[x-y]²
=x[﹙x＋y﹚²－﹙x－y﹚²]
=x[﹙x+y)+(x-y)][﹙x+y)-(x-y)]
=x﹙2x﹚﹙2y﹚
=4x²y
供参考答案3:
x[(x+y)^2-(x-y)^2]
=x[(x+y+x-y)(x+y-(x-y))]
=x*2x*2y
=4x^2y