已知,如图,AB=AD,AC=AE,∠BAD=∠CAE若BC与DE相交于O,与AD相交于F,求证∠B

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因为,在△ABC和△ADE中,AB=AD,∠BAC=∠BAD+∠CAD=∠CAE+∠CAD=∠DAE,AC=AE,
所以,△ABC ≌ △ADE ,
可得：∠ABC = ∠ADE ,
所以,∠BOD = 180°-∠ADE-∠OFD = 180°-∠ABC-∠AFB = ∠BAD .