设y=e的sinx次方,则dy= 设y=e的arctanx次方,则dy=

网友回答

y=e^sinx
则dy=(e^sinx)'dx= e^sinx(sinx)'dx=cosxe^sinxdx
y=e^arctanx
dy=(e^arctanx)'dx= e^arctanx(arctanx)'dx=[e^arctanx/(1+x²)]dx
======以下答案可供参考======
供参考答案1:
y=e^sinx
dy=e^sinx *cosxdx
y=e^arctanx
lny=arctanx
tanlny=x
(sec^2 lny)*(1/y) dy=dx
dy=y/(sec^ 2 lny)=e^arctanx /(sec^2 arctanx)=e^arctanx / (1+x^2)
供参考答案2:
1