解方程(1)(100+x)÷25=5(2)(1+80%)x=360(3)1-25%x=.

发布时间:2020-08-08 10:42:58

解方程
(1)(100+x)÷25=5
(2)(1+80%)x=360
(3)1-25%x=.

网友回答

解:(1)(100+x)÷25=5,
???? (100+x)÷25×25=5×25,
???????????????? 100+x=125,
???????????? 100+x-100=125-100,
???????????????????? x=25;

(2)(1+80%)x=360,
?????????? 1.8x=360,
????? 1.8x÷1.8=360÷1.8,
????????????? x=200;

(3)1-25%x=,
????? ? 1-0.25x=0.25,
? 1-0.25x+0.25x=0.25+0.25x,
??? ?0.25+0.25x=1,
0.25+0.25x-0.25=1-0.25,
????????? 0.25x=0.75,
??? 0.25x÷0.25=0.75÷0.25,
????????????? x=3.
解析分析:(1)根据等式的性质,两边同乘25,得100+x=125,两边再同减去100即可;
(2)原式变为1.8x=360,据等式的性质,两边同除以1.8即可;
(3)原式变为1-0.25x=0.25,据等式的性质,两边同加上0.25x,得0.25+0.25x=1,两边同减去0.25,再同除以0.25即可.

点评:在解方程时应根据等式的性质,即等式两边同加上、同减去、同乘上或同除以某一个数(0除外),等式的两边仍相等,同时注意“=”上下要对齐.
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