y=x除以根号下x^2+1的微分.

网友回答

dy=d(x/√(x^2+1))
={√(x^2+1)*dx-x*2x/[2√(x^2+1)]dx}/(x^2+1)
=1/(x^2+1)^(3/2)*dx
======以下答案可供参考======
供参考答案1:
d(y)=dx/d(√x^2+1)=1/[½(x^2+1)]dx=2(x^2+1)dx
供参考答案2:
rerer