怎么化简(x-1)/(x-3)大于2 化成(x-5)/(x-3)小于0 一步一步一步来 我是数学白痴
网友回答
移项(x-1)/(x-3)>2 => (x-1)/(x-3)-2>0 => [(x-1)-2(x-3)]/(x-3)>0 => (5-x)/(x-3)>0 => (x-5)/(x-3)
======以下答案可供参考======
供参考答案1:
(x-1)/(x-3)>2(x-1)/(x-3)-2>0(x-1)/(x-3)-2(x-3)/(x-3)>0[(x-1)-2(x-3)]/(x-3)>0[x-1-2x+6]/(x-3)>0(-x+5)/(x-3)>0-(x-5)/(x-3)>0(x-5)/(x-3)