已知x+2y=11,x-2y=4,求分式[x/(x^2-2xy+y^2)]÷(x^2+xy+y^2)/(x^3-y^3)+[(2x+2y)/(x-y)-2]的值⊙ o ⊙
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神!自己慢慢算.
这种题适合混时间用!
======以下答案可供参考======
供参考答案1:
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