求解微分方程:y'-y=-sinx

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先求齐次线性微分方程：dy/dx=ylny=c+xy=e^(x+c)常数变异y=c(x)e^xdy/dx=dc(x)/dx*e^x+c(x)*e^x带入原方程得dc(x)/dx=-sin(x)*e^(-x)两边同时积分得c(x)=-1/2(sin(x)+cos(x))*e^(-x)+c带入y=-1/2(sin(x)+cos(x))+c*e...