设函数y=sin(x^2-1),则dy=

网友回答

dy=cos(x^2-1)(x^2-1)'dx
=cos(x^2-1)*2xdx
=2xcos(x^2-1)dx
======以下答案可供参考======
供参考答案1:
2xcos(x^2-1)dx
供参考答案2:
y=f(u)=sinu
u=x^2-1
所以dy=f'(u)*u'dx=cosu*2xdx=2xcos(x^2-1)dx