函数y=sin(3x+π/12)sin(3x-5π/12)的最小正周期为

发布时间：2021-03-16 08:25:33

函数y=sin(3x+π/12)sin(3x-5π/12)的最小正周期为

网友回答

y=sin(3x+π/12)sin(3x-5π/12)
=sin(π/2-3x-π/12)sin(3x-5π/12)
=cos(5π/12-3x)sin(3x-5π/12)
=cos(3x-5π/12)sin(3x-5π/12)
=1/2sin(6x-5π/6)
很明显.W=6
T=2π/W=π/3
======以下答案可供参考======
供参考答案1:
π/3
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