求下列隐函数的微分dy:求下列隐函数的微分dy:1.y=tan(x+y) 2.y^2=x+lny

网友回答

1.dy=[sec(x+y)]^2*d(x+y)
[cos(x+y)]^2*dy=dx+dy
-[sin(x+y)]^2*dy=dx
dy=-[csc(x+y)]^2*dx
2.d(y^2)=d(x+lny)
2ydy=dx+dy/y
(2y-1/y)dy=dx
dy=ydx/(2y^2-1)
======以下答案可供参考======
供参考答案1:
1. dy=1/{【cos（x+y）】^2-1} dx
2. dy=1/(2y-1/y) dx
供参考答案2:
是否还有区间啊，好像DY=DY！—DY2/X！—X2嘛
供参考答案3:
ghd