√1/2-x +√x-1/2 +1 化简:|x-1|-√(x-1)² - √y²-2y+1/y-1√是根号+√x-1/2 +1这种就是+1不在根号里√1/2-x +√x-1/2 +1 化简:|x-1|-√(x-1)² - √y²-2y+1/y-1
网友回答
y>√1/2-x +√x-1/2 +1
先由根号得：X≥1/2,X≤1/2,所以X=1/2
√(y²-2y+1)/(y-1)=√(y-1)²/(y-1)=|y-1|
y>√1/2-x +√x-1/2 +1=1,y>1|x-1|-√(x-1)² - √y²-2y+1/y-1=|x-1|-|x-1|-|y-1|
=-|y-1|=-(y-1)-y+1