0 (n=1、2、3…)（1） 求q的取值范围（2）设bn=a下标（n+2）-1.5a下标（n+1）

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a(n) = aq^(n-1),
a = a(1) = S(1) > 0,q = 1时,S(n) = na > 0.满足要求.
q不等于1时,
S(n) = a[q^n-1]/(q-1).
q>1时,q^n-1>0,q-1>0,S(n) = a[q^n-1]/(q-1) >0.满足要求.
-1-1.b(n) = a(n+2) - 1.5a(n+1) = aq^(n+1) - 1.5aq^n = aq^n[q-1.5].
q = 1时,b(n) = a(-0.5),T(n) = -na/2,S(n) = na > -na/2 = T(n).
q > -1且q不等于1时,T(n) = aq(q-1.5)[q^n-1]/(q-1),S(n) = a[q^n-1]/(q-1).
T(n) - S(n) = a[q^n-1]/(q-1)[q(q-1.5) - 1] = a[q^n-1][2q^2 - 3q - 2]/[2(q-1)] = a[q^n-1][2q+1][q-2]/[2(q-1)]
-1 0,
T(n) > S(n).q = -1/2时,T(n) - S(n) = a[q^n-1][2q+1][q-2]/[2(q-1)] = 0,
T(n) = S(n).
-1/2 T(n) 1 T(n) q = 2时,T(n) - S(n) = a[q^n-1][2q+1][q-2]/[2(q-1)] = 0,
T(n) = S(n).
q > 2时,T(n) - S(n) = a[q^n-1][2q+1][q-2]/[2(q-1)] > 0,T(n) > S(n).综合,有-1 S(n).
q = -1/2时,T(n) = S(n).
-1/2 q = 2时,T(n) = S(n).
q > 2时,T(n) > S(n).