已知f(x)=ax5+bx3+cx+1,且f(2012)=3,则f(-2012)=________.
网友回答
-1
解析分析:由于x=2012时,ax5+bx3+cx+1=3,把x=2012代入ax5+bx3+cx+2=8中,可以解得20125a+20123b+2012c的值,然后把x=-2012代入所求代数式,整体可求
解答:∵f(2012)=a×20125+b20123+2012c+1=3
∴a×20125+b20123+2012c=2
∴f(-2012)=a×(-2012)5+b×(-2012)3+(-2012c)+1
=-[a×20125+b20123+2012c]+1=-2+1=-1
故