递等式计算.
(1)4.7+3.2×0.4÷1.6
(2)13×65+16892÷82
(3)(2-)÷(+)
(4)[1(+)]÷0.25
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解:(1)4.7+3.2×0.4÷1.6
=4.7+3.2÷1.6×0.4,
=4.7+2×0.4,
=4.7+0.8,
=5.5;
(2)13×65+16892÷82
=845+206,
=1051;
(3)(2-)÷(+)
=÷,
=4;
(4)[1×(+)]÷0.25
=[1×],
=×4,
=.
解析分析:(1)可根据乘法交换律计算;
(2)(3)(4)根据四则混合运算的运算顺序计算即可:先算乘除,再算加减,有括号的要先算括号里面的.
点评:在运用递等式计算时,要注意计算过程的完整性,中间不要有太大跳跃.