先化简[(a-1)分之1-(a+1)分之1]÷（2a²-2）分之a
网友回答
原式=(a+1-a+1)/(a+1)(a-1)÷a/2(a+1)(a-1)
=2/(a+1)(a-1)×2(a+1)(a-1)/a
=4/a======以下答案可供参考======
供参考答案1:
[(a-1)分之1-(a+1)分之1]÷（2a²-2）分之a
=[(a²-1)分之(a+1)-(a²-1)分之(a-1)]÷（2a²-2）分之a
=[(a²-1)分之(a+1-a+1)]÷[2(a²-1）分之a]
=[(a²-1)分之2]×[a分之2(a²-1)]
=a分之4