发布时间:2021-02-19 21:42:45
(本小题满分12分) 设a > 1,函数.(1)求的反函数;(2)若在[0,1]上的最大值与最小值互为相反数,求a的值;(3)若的图象不经过第二象限,求a的取值范围.
解:(1) 由
∴
∴··································································· 4分
(2) ∵ a > 1 ∴在[0,1]上递增
∴,
∴ 即
∴······························································································· 8分
(3) 在y轴上的截距为
要使的图象不过第二象限,
只需
∴
∴
因此,a的取值范围为····································································· 12分
解析