tan(a+b)=5/2,tan(b-4/π)=4/1 求tan(a+4/π)的值
网友回答
tan(a+4/π)
=tan((a+b)-(b-π/4))
=(tan(a+b)-tan(b-π/4)))/(1+tan(a+b)tan(b-π/4))
=(2/5-1/4)/(1+(2/5)(1/4))
=(3/20)/(1+2/20)
=3/22======以下答案可供参考======
供参考答案1:
tan(a+b)=5/2,tan(b-4/π)=4/1 求tan(a+4/π)
tan(a+4/π)=tan[a+b-(a-π/4)】=(5/2-4)/1+5/2*4=-3/20