已知吗的平方+2m+n的平方-8n+17=0,则m的n次方=

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m^2+2m+n^2-8n+17=0
m^2+2m+1+(n^2-8n+16)=0
(m+1)^2+(n-4)^2=0
所以有(m+1)^2=0 => m=-1(n-4)^2=0 => n=4则有m^n=(-1)^4=1
======以下答案可供参考======
供参考答案1:
m^2+2m+n^2-8n+17=0
(m+1)^2+(n-4)^2=0
m=-1 n=4
m^n=(-1)^4=1