2分之跟2乘以（2根12+4根1/8-3根48）

其他回答

√2/2(2√12+4√1/8-3√48)

=√2/2(4√3+√2-12√3)

=√2/2(√2-8√3)

=1-4√6

本题：√2/2*[2√12+4√(1/8)-3√48]

=√2/2*（4√3+√2-12√3）

=2√6+1-6√6

=1-4√6

√2/2×[2√12+4√(1/8)-3√48]

=√2/2×(4√3+√2-12√3)

=√2/2×(√2-8√3)

=1-4√6

(1/2)√2*[2√12+4√(1/8)-3√48]

=(1/2)√2*(4√3+√2-12√3)

=(1/2)√2*(√2-8√3)

=(1/2)√2*√2-(1/2)√2*8√3

=1-4√6

解答

2√2(2√12+4√1/8-3√48)=2√2(2√(3*4)+√(2/16)-3√(3*16)=2√2*(2*2√3 + 1/4√2 - 3*4√3)=2√2 * (4√3+1/4√2-12√3)=2√2*(1/4√2-8√3)=2√2 * 1/4√2 - 2√2*8√3=1-16√6