(1)(5a2+2a)-4(2+2a2);(2)5x2(x+1)(x-1);(3)(x+3y)2-(2x+y)(x-y);(4)4(m+1)2-(2n+5)(2m-5

发布时间:2020-08-13 07:45:11

(1)(5a2+2a)-4(2+2a2);
(2)5x2(x+1)(x-1);
(3)(x+3y)2-(2x+y)(x-y);
(4)4(m+1)2-(2n+5)(2m-5).

网友回答

解:(1)(5a2+2a)-4(2+2a2),
=5a2+2a-8-8a2,
=-3a2+2a-8;

(2)5x2(x+1)(x-1),
=5x2(x2-1),
=5x4-5x2.

(3)(x+3y)2-(2x+y)(x-y),
=x2+6xy+9y2-2x2+2xy-xy+y2,
=-x2+8xy+10y2;

(4)4(m+1)2-(2n+5)(2m-5),
=4m2+8m+4-4mn+10n-10m+25,
=4m2-4mn-2m+10n+29.
解析分析:(1)去括号,合并同类项;
(2)利用平方差公式和单项式乘多项式的法则进行计算;
(3)(4)运用完全平方公式和多项式的乘法计算,再合并同类项.


点评:本题考查的是有理数的运算能力.注意:
(1)要正确掌握运算顺序,在混合运算中要特别注意运算顺序:先三级,后二级,再一级;有括号的先算括号里面的;同级运算按从左到右的顺序;
(2)去括号法则:--得+,-+得-,++得+,+-得-.
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