计算:(1)(x-2y)(x+3y)(2)(x-1)(x2-x+1)(3)(-2x+9y2)(x2-5y)(4)(2a2-1)(a-4)-(a2+3)(2a-5)

发布时间:2020-08-13 00:35:15

计算:
(1)(x-2y)(x+3y)
(2)(x-1)(x2-x+1)
(3)(-2x+9y2)(x2-5y)
(4)(2a2-1)(a-4)-(a2+3)(2a-5)

网友回答

解:(1)(x-2y)(x+3y),
=x2+3xy-2xy-6y2,
=x2+xy-6y2;

(2)(x-1)(x2-x+1),
=x3-x2+x-x2+x-1,
=x3-2x2+2x-1;

(3)(-2x+9y2)(x2-5y),
=-x3+10xy+3x2y2-45y3;

(4)(2a2-1)(a-4)-(a2+3)(2a-5),
=2a3-8a2-a+4-(2a3-5a2+6a-15),
=2a3-8a2-a+4-2a3+5a2-6a+15,
=-3a2-7a+19.
解析分析:根据多项式相乘,先用一个多项式的每一项乘以另一个多项式的每一项,再把所得的积相加计算,有同类项的再合并同类项.

点评:本题主要考查多项式乘多项式的运算,熟练掌握运算法则是解题的关键,计算时要注意符号的处理.
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