若x+y=2m+1,xy=1,且21x2-48xy+21y2=2010.则m=________.
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解析分析:首先进行配方,即21x2-48xy+21y2=21x2+42xy+21y2-90xy=21(x+y)2-90xy,然后根据题意即可推出m的值.
解答:∵21x2-48xy+21y2=21x2+42xy+21y2-90xy=21(x+y)2-90xy,
∵21x2-48xy+21y2=2010,∴21(x+y)2-90xy=2010,
∵x+y=2m+1,xy=1,
∴(2m+1)2=100
∴2m+1=±10
∴m=,m=.
故