将下列各式分解因式:(1)x2-9y2(2)x3-2x2y+xy2(3)2x(a-b)-(b-a)(

发布时间:2021-02-25 06:04:59

将下列各式分解因式:(1)x2-9y2(2)x3-2x2y+xy2(3)2x(a-b)-(b-a)(4)x2-4y2-3x+6y.

网友回答

(1)x2-9y2=(x+3y)(x-3y);
(2)x3-2x2y+xy2
=x(x2-2xy+y2)=x(x-y)2;(3)2x(a-b)-(b-a)
=(a-b)(2x+1);(4)x2-4y2-3x+6y=(x+2y)(x-2y)-3(x-2y)=(x-2y)(x+2y-3).
======以下答案可供参考======
供参考答案1:
(1)(x 3y)(x-3y) (2)x(x-y)(x-y) (3)(2x 1)(a-b) (4)(x 2y-3)(x-2y)
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