有两个自然数相除,商是17,余数是13,已知被除数、除数、商与余数之和等于2113,则被除数是________.
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1968
解析分析:设除数为x,根据“被除数=商×除数+余数”得:(17x+13)+x+17+13=2113,解这个方程,求出除数,进而根据“被除数=商×除数+余数”解答即可.
解答:设除数为x,则:
(17x+13)+x+17+13=2113,
??????????? 18x+43=2113,
??????? ?18x+43-43=2113-43,
?????????????? 18x=2070,
???????????????? x=115,
115×17+13,
=1955+13,
=1968;
答:被除数是1968;
故